a 3000kg truck moving at a speed of 72km/h stop after covering some distance the force applied by brakes is2400N compute the distance covered and work done by this force
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kinetic energy=workdone by force
1/2mv^2=F.S
1/2 x 3000 x (20)^2=2400 x S
1500 x 400= 2400 x S
S=1500/6=250m
here v=72km/h=72x5/18=20m/sec
1/2mv^2=F.S
1/2 x 3000 x (20)^2=2400 x S
1500 x 400= 2400 x S
S=1500/6=250m
here v=72km/h=72x5/18=20m/sec
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