A 300g ball travelling at 50m/s strikes the palm of the player's hand is stop him 10 s .find the force exerted by the ball on the hand.
Answers
Answered by
1
[0010001111]... Hello User... [1001010101]
Here's your answer...
m = 0.3 kg
u = 50 m/s
v = 0 (as the ball stops)
t = 10 s
v = u-at (as acceleration is negative)
0 = 50 - 10a
10a = 50
a = 5 m/s²
F = ma
= 0.3×5
= 1.5 N
The player exerts a force of 1.5 N to stop the ball.
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
Here's your answer...
m = 0.3 kg
u = 50 m/s
v = 0 (as the ball stops)
t = 10 s
v = u-at (as acceleration is negative)
0 = 50 - 10a
10a = 50
a = 5 m/s²
F = ma
= 0.3×5
= 1.5 N
The player exerts a force of 1.5 N to stop the ball.
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
Similar questions