A 300m train running with a speed of 136km/hr in what time will it pass a cycle that is running at 6 km/hr in opposite direction
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Firstly add cycle speed in train speed
136+6=142
Then change
142×5/18=39.44m/s
t=s/v
300/39.44=7.6s
136+6=142
Then change
142×5/18=39.44m/s
t=s/v
300/39.44=7.6s
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