Question

A 30ft ladder is leaning against a building if the foot of the ladder is 10ft away frim the base of the building does the ladder reach. ​

Answer 1

Answer:

20√2 ft or 28.2 ft

ABC is right triangle

right angled at B

we know

AB² + BC² = AC²

AB² + 10² =30²

AB² = 900 - 100

AB² = 800 ft

AB = √800

AB = 20√2 ft

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Height\:of\:wall=20}\sqrt{2}\:ft}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a 30ft ladder is leaning against a building if the foot of the ladder is 10ft away from the base of the building.

• Wh have to find the height of wall.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\: ladder =30\:ft} \\ \\ : \implies \text{Distance\:between\:wall\:and\:foot\:of\: ladder=10ft}\\ \\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Heigh\:of\:wall=?}$

• Accroding to given question :

$\bold{In \: \triangle \: ABC} \\ : \implies {h}^{2} = {p}^{2} + {b}^{2} \: \: \: \: \: \: \: \: \text{(by \: pythagoras \: theorem}) \\ \\ : \implies {30}^{2} = {(AB)}^{2} + {10}^{2} \\ \\ : \implies (AB)^{2} =900-100\\ \\ : \implies {(AB)}^{2} =800 \\ \\ : \implies AB= \sqrt{800} \\ \\ \green{: \implies \text{AB=20}\sqrt{2}\:ft}$