Math, asked by nithin9360, 6 months ago

A 34 cm long wire is bent in to a rectangle. The length of its diagonal is 13 cm. What

are the lengths of the sides of the rectangle​

Answers

Answered by Anonymous
33

Answer:

MATHS

A 34 cm long wire is bent in to a rectangle. The length of its diagonal is 13 cm. What are the lengths of the sides of the rectangle?

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ANSWER

Perimeter of the rectangle = Length of the wire 2(Length + Breadth) = 34

⇒ Length + Breadth = 17

Let the length of the rectangle be x cm.

⇒ Breadth of the rectangle = (17 - x) cm.

Using Pythagoras theorem,

x

2

+(17−x)

2

=13

2

x

2

+289−34x+x

2

=169

2x

2

−34x+120=0

x

2

−17x+60=0

Discriminant =b

2

−4ac=289−240=49

x=

2a

−b±

b

2

−4ac

=

2

17±

49

=

2

17±7

=12or5

When length, x = 12 cm, breadth, 17 - x = 5 cm

When length, x = 5 cm, breadth, 17 - x = 12 cm

Thus, the lengths of the sides of the rectangle are 12 cm and 5 cm.

Answered by nirmalanagraj9
1

Answer:

Perimeter of the rectangle = Length of the wire 2(Length + Breadth) = 34

⇒ Length + Breadth = 17

Let the length of the rectangle be x cm.

⇒ Breadth of the rectangle = (17 - x) cm.

Using Pythagoras theorem,

x 2+(17−x) 2

=13

2x 2+289−34x+x 2

=169

2x 2−34x+120

=0

x 2−17x+60

=0

Discriminant =b

2−4ac=289−240=49

x= 2a−b± b 2-4ac

= 217±49

= 217±7

=12or5

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