Question

A 36 year old female have 2 child. If menses start at the age of 12 year then calculate the number of secondary oocyte and ova on till age

Answer 1

The female is 36 year old and menses start at the age of 12 ,that is menses occurred for 36–12=24 years or 24×12=288 months , 288 secondary oocytes should have formed but she got pregnant twice so no secondary oocyte formed for 9(gestation period)×2 = 18 months and 6 months following parturition that is lactational period in each pregnancy.(6×2=12)

So, no secondary oocytes formed for 18+12=30months. Hence , 288–30=258.

And 2 secondary oocytes developed into ova which fertilised to give the 2 zygotes.

Answer 2

$\sf{\underline{Answer:}}$

258 secondary oocyte and 2 ova.

$\sf{\underline{Because:}}$

Ova is released only at the time of fertilisation.

2 babies means two ova.

$\implies$ $\sf{(36 - 12) \times 12 = x}$

$\implies$ $\sf{24 \times 12 = x}$

$\implies$ $\sf{288 = x}$

Therefore: $\boxed{\sf{288}}$

$\sf{\underline{But:}}$

2 babies means no secondary oocytes were produced for 9 months (at the time of pregnancy).

$\sf{\underline{Note:}}$ And moreover, 6 months till breast feeding.

$\sf{\underline{So:}}$

$\implies$ $\sf{2(9 + 6) = x}$

$\implies$ $\sf{2(15) = x}$

$\implies$ $\sf{30 = x}$

Therefore: $\boxed{\sf{30}}$

$\sf{\underline{Hence:}}$

$\boxed{\sf{288 - 30 = 258}}$ secondary oocyte.