Question

a+3b+3c=1 ;-a-2b-2c=0;-b+c=0 ans b=1/2 ,c=1/2,a=-2. pls can any one explain me how it came pls i want explaination how it happen

Answer 1

Answer:

Step-by-step explanation: Apply the rule of variable elimination method

a+3b+3c=1; (eq.1)

-a-2b-2c=0; (eq.2)

-b+c=0; (eq.3)

By eq. 3 we get

c=b;

Put this values in eq. 1 and eq. 2;

we get;

Eq. 1 as:     a+3b+3b=1; a+6b=1

Eq.2 as: -a-2b-2b=0: -a-4b=0:

Adding these two equation: (a is eliminate);

2b=1; b=1/2 and c=-1/2

and put the value of b in the a+6b=1;

we get

a+3=1; a=1-3=-2

Answer 2

Answer:

Step-by-step explanation: