Math, asked by raj2777, 10 months ago

(a^3b+6a^2b^2-7ab+4)+(-7a^2 b^2++2a^3b+6ab-1)​

Answers

Answered by Thegreatsk
1

Answer:

3a^2b - a^2b^2 - ab + 3 is the answer

Attachments:
Answered by amitnrw
0

Answer:

a³b + 6a²b² - 7ab + 4  - 7a²b² + 2a³b + 6ab - 1  = 3a³b  - a²b² - ab + 3

Step-by-step explanation:

(a^3b+6a^2b^2-7ab+4)+(-7a^2 b^2++2a^3b+6ab-1)​

= a³b + 6a²b² - 7ab + 4  - 7a²b² + 2a³b + 6ab - 1

Taking similar terms together

= a³b + 2a³b  + 6a²b²  - 7a²b²- 7ab + 6ab + 4 - 1

= 3a³b  - a²b² - ab + 3

a³b + 6a²b² - 7ab + 4  - 7a²b² + 2a³b + 6ab - 1  = 3a³b  - a²b² - ab + 3

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