(-a+3b-c)² expand using identities
Answers
Answered by
1
Answer:
= (-a)² + (3b)² - (c)²
= -a² + 9b - c²
Answered by
19
Some Identities:-
- (a + b)² = a²+ 2ab + b²
- (a - b)² = a² - 2ab +b²
- (a² - b²) = (a + b) (a - b)
- (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca.
Solution:-
( - a + 3b - c ) ²
[•°• (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca.]
a² - 6ab + 2ac + 9b² - 6bc
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< hope its helpful for you >
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