Question

-a-3b take 1/2a+1/3b-1/2c​

Answer 1

Answer:

Using identity - (a+b+c)^2= a^2 + b^2 +c^2 +2ab +2bc + 2ca  

We get ,

(1/2a)^2+ (-1/3b)^2+ (c)^2 +{ 2(1/2a)(-1/3b)} +{2 (-1/3b)(c) }+ {2 (c) (1/2a)}

= a - 2/3b + c^2 -1/3ab -2/3bc +ac