Question

A 3cm object is placed in front of a concave mirror and imag formed is 9cm in height what is the magnification of this object?

Answer 1

Given :

• Height of Object (ho) = 3cm
• Height of image (hi) = 9cm

To Find :

• Mangnindication

Formula Used :

$\bullet\underline{\boxed{\sf m=\dfrac{Height\; of \; image }{Height \; of \; object}}}$

Solution :

$\implies{\sf m=\dfrac{h_i}{h_o} }$

$\implies{\sf m =\dfrac{9}{3} }$

$\implies{\sf m = +3}$

Answer :

Magnification of object is +3

_________________________________

➞ Extra Info.

Magnification ⠀⠀⠀⠀⠀⠀⠀⠀⠀ Image

| m | > 1 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ enlarged

m < 0 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀inverted

| m | < 1⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀diminished

m > 0⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ erect

Answer 2

Answer:

$\huge\bf{GIVEN\:}$

❏ Height of the Object(h1) = 3 cm

❏ Height of the Image(h2) = 9 cm

To Find

$\bold\orange{Magnification\:Of\:the\:Object\:-\: ?}$

Formula -

$\bf\boxed {m\:= \frac{Height\:of\:image}{Height\:of\:Object}}$

$\bold\blue{Solution}$

$\bf\implies {m\:= \frac{h2}{h1}}$

$\bf\implies {m\:= \frac{9}{3}}$

$\bf\implies {m\:=\:3}$

$\fbox\bold\green{Magnification\:of\: Object\:is\:+3}$