Question

A 3digit number 4a3 is added to another 3digit number 984 to give four digit number 13b7 which is divisible by 11 .find (a+b)

Answer 1

Hey,sup!

As per the question,

4a3+984=13b7 which is divisible by 11.

We know that a number is divisible by 11 if the difference of sum of alternate digit is either 0 or multiple of 11.

The value of a can be 0,1or 2 as we can see and the value of b can be only 8 or 9.
By putting a=1
413+984=1397. Gives b= 9.

1397 is divisible by 11.

So a+b= 1+9=10.
Hope it helps.

Answer 2

it's 10 the answer of this question .......
$452 {?}^{2}$