A (- 4, -1), B( -1 , 2 ) and C ( p, 5 ) are the vertices of an isosceles triangle. Find the value of p,
given that AB is the unequal side.
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Answer:
P = -7
Step-by-step explanation:
If the points are vertices then lenth of two sides is equal
Now according to the question,
Points are (-4, -1) and (-1, 2) and (p, 5)
So distance between points
(-4 - p) ^2 +(-1 - 5 ) ^2 = ( p+1) ^2 + (5 - 2) ^2
16 + p^2 + 8p + 36 = p^2 + 1 + 2p + 9
6p = -42
p = -7
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