Math, asked by vatsalyagupta7733, 4 months ago

A (- 4, -1), B( -1 , 2 ) and C ( p, 5 ) are the vertices of an isosceles triangle. Find the value of p,
given that AB is the unequal side.​

Answers

Answered by rudra1402729
1

Answer:

P = -7

Step-by-step explanation:

If the points are vertices then lenth of two sides is equal

Now according to the question,

Points are (-4, -1) and (-1, 2) and (p, 5)

So distance between points

(-4 - p) ^2 +(-1 - 5 ) ^2 = ( p+1) ^2 + (5 - 2) ^2

16 + p^2 + 8p + 36 = p^2 + 1 + 2p + 9

6p = -42

p = -7

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