A 4 22 resistance wire is doubled on it. Calculate the new resistance of the wire.
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Correct Question :
A 4 ohm resistance wire is doubled on it. Calculate the new resistance of the wire.
AnswEr :
- The new resistance of the wire is 1 ohm.
Step-by-step explanation :
We're given with the resistance of the wire, that is, 4Ω . We're supposed to find the new resistance if the wire itself is doubled .
Now,
We know that if the wire is doubled then, the length of the wire will be halved and area would be doubled .
Before proceeding to the question, we need to know about the concept of Resistivity.
Resistivity of a wire is given by,
R = pL/A
Where,
- p is the resistivity of the material
- L is the length of the wire
- A is the area of cross-section of the wire
Let's assume R1 is the new resistance.
So,
➜ R1 = P(L/2) / 2A [As wire is doubled the length of the wire will be halved and area would be doubled ]
Taking the ratio of old and new resistance,
⇛ R1/R = [P × (L/2) / 2A] / [PL/A]
⇛ R1/R = 1/4
⇛ R1 = R/4
⇛ R1 = 4/4 [ As the value of R is 4Ω]
⇛ R1 = 1 Ω
Hence, the new resistance of the wire is 1 ohm .
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