Math, asked by satwika7400, 1 day ago

a^4-3a^2+1=0হলে a^+1/a^2এর মান কত

Answers

Answered by anindyaadhikari13
14

সমাধান:

দেওয়া আছে:

 \rm \longmapsto {a}^{4} - 3 {a}^{2}  + 1 = 0

 \rm \longmapsto {a}^{4} - 3 {a}^{2}  =  - 1

 \rm \longmapsto {a}^{2}( {a}^{2}  - 3 )  =  - 1

 \rm \longmapsto  {a}^{2}  - 3= \dfrac{ - 1}{ {a}^{2} }

 \rm \longmapsto  {a}^{2} +  \dfrac{1}{ {a}^{2} }   - 3=0

 \rm \longmapsto  {a}^{2} +  \dfrac{1}{ {a}^{2} } = 0 + 3

 \rm \longmapsto  {a}^{2} +  \dfrac{1}{ {a}^{2} } =3

সুতরাং, a² + 1/a² এর মান হল ৩.

উত্তর:

  • a² + 1/a² এর মান হল ৩

আরো জানুন:

  • (a + b)² = a² + 2ab + b²
  • (a - b)² = a² - 2ab + b²
  • a² - b² = (a + b)(a - b)
  • (a + b)³ = a³ + 3ab(a + b) + b³
  • (a - b)³ = a³ - 3ab(a - b) - b³
  • a³ + b³ = (a + b)(a² - ab + b²)
  • a³ - b³ = (a - b)(a² + ab + b²)
  • (x + a)(x + b) = x² + (a + b)x + ab
  • (x + a)(x - b) = x² + (a - b)x - ab
  • (x - a)(x + b) = x² - (a - b)x - ab
  • (x - a)(x - b) = x² - (a + b)x + ab
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