Question

A(-4,4) K(-2,5/2) ,N(4,-2) are collinear or not

Use slope of line formula. = y2 - y1 / x2 - x1
It has to be collinear but Wt is the answer , no rubbish reply ,,, divide 5/2 properly n show each statement
Will be marked as brainliest

Answer 1

Given points are A(-4,4), K(-2,5/2), N(4,-2).

Let us consider the points AK:

x1 = -4, y1 = 4, x2 = -2, y2 = 5/2

$m = \frac{y2 - y1}{x2 - x1}$

$= \ \textgreater \ \frac{ \frac{5}{2} - 4 }{-2 - (-4)}$

$= \ \textgreater \ \frac{ \frac{5}{2} -4 }{2}$

$= \ \textgreater \ \frac{-3}{ \frac{2}{2} }$

$= \ \textgreater \ \frac{-3}{4}$

Now,

Let us consider the points KN:

x1 = -2, y1 = 5/2, x2 = 4, y2 = -2

$m = \frac{y2 - y1}{x2- x1}$

$= \ \textgreater \ \frac{-2 - \frac{5}{2} }{4 - (-2)}$

$= \ \textgreater \ \frac{-2 - \frac{5}{2} }{4 + 2}$

$= \ \textgreater \ \frac{-2 - \frac{5}{2} }{6}$

$= \ \textgreater \ \frac{-9}{ \frac{2}{6} }$

$= \ \textgreater \ \frac{-9}{12}$

$= \ \textgreater \ \frac{-3}{4}$



The given points are collinear.



Hope this helps!

Answer 2

Hi,

Please see the attached file!



Thanks