Question

a/4=b/5=c/9, prove that (a+b+c)/9=2

Answer 1

⛤HERE IS YOUR ANSWER⛤

$\frac{a}{4} = \frac{b}{5} = \frac{c}{9} = k \: (say)$

So, a = 4k, b = 5k and c = 9k.

Now, LHS
$= \frac{a + b + c}{9} \\ = \frac{4k + 5k + 9k}{9} \\ = \frac{18k}{9} \\ = 2k \\ = 2 \: (since \: k \: is \: any \: constant \: we \: put \: k = 1)$
= RHS (Proved)

⛤HOPE THIS ⬆ HELPS YOU⛤