A 4 cm tall object is placed at a distance of 7.5 cm in front of the plane mirror . Calculate
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Answers
Explanation:
Height of object, h
0
=3cm
Object distance, u=7.5cm
Focal length, f=6cm
from mirror formula
f
1
=
v
1
+
u
1
6
1
=
v
1
−
7.5
1
v
1
=
6
1
+
7.5
1
v=3.33cm
magnification, m=
h
0
h
i
=−
u
v
⇒
3
h
i
=
−7.5
−3.33
⇒ h
i
=1.332cm
Image will be 3.33cm on the right side of the mirror and will be virtual.
Height of the image will be 1.332cm
Correct Question:
A 4 cm tall object is placed at a distance of 7.5 cm in front of the plane mirror . Calculate it's image distance and height of the image.
Answer:
image distance = 15 cm, height of image = 4 cm
Explanation:
Given that a 4 cm tall object is placed at a distance of 7.5 cm in front of the plane mirror. We need to find out it's image distance.
Now,
In case of plane mirrors; the object distance is equal to the image distance. Therefore, the image distance is twice or two times the sum of object distance i.e. (7.5 + 7.5) 15 cm. Also, the image size is same as that of the object size i.e. 4 cm and formed image is upright.
Hence, the image distance from the plane mirror is 15 cm.
Focal length of plane mirror is infinity. Because when a ray of light strikes the plane mirror, it reflects back in a parallel way (means parallel to each other). In this way then we can meet at infinity or maybe never.