Question

A 4 kg ball is thrown upward with a velocity of 20 m/s. Find the potential energy at maximum height

Answer 1

Now at maximum height v=0

So applying
V²=u² +2 as
0=400-2gs
S=400/20= 20m

Now potential energy =mgh
= 4*10*20 = 800 J

Thanks for asking

Note: the answer may differ as I have used g=10 instead of 9.8 for the sake of simplicity

Answer 2

At maximum height v=0

Now,

v²=u² +2 as

0=400-2gs

S=400/20= 20m

potential energy =mgh

= 4*10*20 = 800 J