A 4 micro Farad capacitor is charged by a 200 volt supply. the supply is then disconnected and the charged capacitor is connected to another uncharged 2 microfarad capacitor. how much electrostatic energy of the first capacitor is lost in the process of attending this study situation.
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Answer:
The loss of Electrical Energy is 400N.
Explanation:
Here,
Electrostatic Energy of first capacitor= (200×4)= 800N
Again, Electrostatic Energy in the second capacitor= (200×2)= 400N
So, the loss of Electrical Energy= 800-400= 400N
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