Question

a 4 ohm a 52 ohm resistor are connected in series with 12.0 V .What is the current in the circuit

Answer 1

Here Is Your Ans ⤵

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Given ,

R1 = 4

R2 = 52

V = 12.0

We know That ,

R = R1 + R2

R = 4 + 52

R = 56

R = V × I

I = R / V

I = 56 / 12.0

I = 4.666666667 Amp

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