Question

A 4-pole, D.C. generator has a wave- Wound armature with 792 conductors . the flux per pole is 0.0121 WB. Determine the speed at which it is should be run to generate 240V on no- load​

Answer 1

Answer:

ok

Explanation:

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Answer 2

Given:

Number of poles = 4

Number of conductors wounded= 792

The flux per pole = 0.0121 WB

To find:

The speed at which it is should be run to generate 240V on no-load​

Solution:

Energy = $\frac{P \phi V Z }{ \omega a}$

where P = number of poles

∅ = Flux per pole

V= speed of the generator

Z = Number of conductors

ω = 60

a =2

Substituting the values,

240 = 4 X 0.0121 X V X 792 / 60 X 2

or V = 240 X 120 / 4 X 0.0121 X 792

= 751.3 rpm

Hence, the required speed is 751.3 rpm.