A 4 Ω resistance wire is doubled on it. Calculate the new resistance of the wire.
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Given,
R = 4 Ω
We know that,
R = ρ l/A - (i)
4 = ρ l/A - (ii)
If a wire is doubled on it, then new area = A'
= 2A
and
new length = l'
= l/2
New resistance of the wire = ρ l'/A'
= ρ (l/2)/(2A)
= ρ l/2*2*A
= 1/4 (ρ l/A)
From equation (i)
= 1/4 R
From equation (ii)
= 1/4 * 4
= 1 Ω Ans.
Ans.) The new resistance of the wire is 1 Ω.
R = 4 Ω
We know that,
R = ρ l/A - (i)
4 = ρ l/A - (ii)
If a wire is doubled on it, then new area = A'
= 2A
and
new length = l'
= l/2
New resistance of the wire = ρ l'/A'
= ρ (l/2)/(2A)
= ρ l/2*2*A
= 1/4 (ρ l/A)
From equation (i)
= 1/4 R
From equation (ii)
= 1/4 * 4
= 1 Ω Ans.
Ans.) The new resistance of the wire is 1 Ω.
Answered by
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Given,
R = 4 Ω
We know that,
R = ρ l/A - (i)
4 = ρ l/A - (ii)
If a wire is doubled on it, then new area = A'
= 2A
and
new length = l'
= l/2
New resistance of the wire = ρ l'/A'
= ρ (l/2)/(2A)
= ρ l/2*2*A
= 1/4 (ρ l/A)
From equation (i)
= 1/4 R
From equation (ii)
= 1/4 * 4
= 1 Ω Ans.
Ans.) The new resistance of the wire is 1 Ω.
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