A 4Π resistance wire is doubled on it . Calculate the new resistance of the wire.
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Answer:
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Explanation:
We consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled. Thus, R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.
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