A 40 kg boy sit 1.2m from the fulcrum of a see-saw. Where should the another boy of 30 kg sit on the other side in order tobalance it?
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Answer:
distance=1.6 m
Explanation:
For equilibrium
torque on left side = torque on right side
r1 x F1 = r2 x F2
1.2 x 40 = r2 x 30
48 = r2 x 30
48/30 = r2
1.6 m = r2
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