a 40 kg shell is flying at speed of 72km/hr.It explodes into 2 pieces one piece of mass 15kg just slops. what is the speed of other ?
Answers
Answered by
212
Hello friend
As momentum is always conserved
total initial momentum = total final momentum
Mathematically,
m1u1 + m2u2 = m1v1 + m2v2
Here m=40kg
and u= 72km/hr=20m/s
m1=15kg
v1=0
m2=40-15=25kg
we need to find v2
So
40×20 = 15×0+25×v2
800=25v2
v2=32
So the speed of the other will be 32m/s
HOPE IT HELPS.... :-)
As momentum is always conserved
total initial momentum = total final momentum
Mathematically,
m1u1 + m2u2 = m1v1 + m2v2
Here m=40kg
and u= 72km/hr=20m/s
m1=15kg
v1=0
m2=40-15=25kg
we need to find v2
So
40×20 = 15×0+25×v2
800=25v2
v2=32
So the speed of the other will be 32m/s
HOPE IT HELPS.... :-)
Answered by
39
First find the speed of one kg
72/40=1.8 is the speed of one kg.
Now the speed of 15 kg=1.8×15=27km/h
The speed of other=40-15=25
=25×1.8=45km/h.
Hope its helpful
72/40=1.8 is the speed of one kg.
Now the speed of 15 kg=1.8×15=27km/h
The speed of other=40-15=25
=25×1.8=45km/h.
Hope its helpful
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