Question

three times the smallest of three consecutive odd numbers decreased by 7 equals twice te largest one. Find the numbers.

Answer 1

Let the numbers be x; x+2;x+4
Atq 3x-7=2(x+4)
3x-7=2x+8
x=15
x+2=17
x+4=19

Answer 2

Let the numbers be x, x+2 & x+4

ATQ,
(3x-7) = 2(x+4)
3x-7 = 2x+8
3x-2x = 8+7
x=15

Thus,
No. are :
x=15
x+2=15+2=17
x+4=15+4=19

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