A 40 kg skater moving at 4m s eastwards collides head on with a 60 kg skater travelling at 3m s westwards . if the two skates remain in contact, what is their final velocity?
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Given:
Mass of first skater =m1=40kg
Mass of second skater=m2=60kg
Initial velocity of first skater=4m/s ( towards east considered as positive)
Initial velocity of second skater=-3m/s( towards west, considered as neagtive0
By law of conservation of momentum, we get
mu1+m2u2=(m1+m2)V( as both bodies move together)
40*4-60*3=100V
v=-0.2m/s
Mass of first skater =m1=40kg
Mass of second skater=m2=60kg
Initial velocity of first skater=4m/s ( towards east considered as positive)
Initial velocity of second skater=-3m/s( towards west, considered as neagtive0
By law of conservation of momentum, we get
mu1+m2u2=(m1+m2)V( as both bodies move together)
40*4-60*3=100V
v=-0.2m/s
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