Question

A 40 kg wheel in the form of a uniform circular disc 200 centimetre in diameter is making 120 RPM calculate 1.angular momentum 2.moment of inertia disc=1/2MR×MR

Answer 1

we have M= 40kg D= 200 cm so R= 1 m
so we have
$i = m \frac{ {r}^{2} }{2}$
$i = 40 \: kg \: {m}^{2}$

so the angular momentum is given by
$L = I ω$
$L = 40 \times \frac{120}{60} = 80 \:kg {m}^{2} {s}^{ - 1}$