Question

A 400 mg iron capsule contains 100 mg of ferrous fumarate,
(CHCOO)2 Fe. The percentage of iron present in it is
approximately
(a) 33%
(b) 25%
(c) 14%
(d) 8%​

Answer 1

Answer:

8%

Explanation:

Step 1 : Calculate the molar mass of ferrous fumarate.

(CHCOO)2 Fe

Molar = 12 × 2 + 1 × 2 + 12 × 2 + 16 × 2 + 16 × 2 + 56 = 170 g/mol

Step 2 : Calculate the mass of iron in Ferrous Fumarate.

56/170 × 100 = 32.94 grams.

Step 3 : Calculate the percentage of Iron in Ferrous fumarate.

32.94/400 × 100% = 8.235%

Step 4 : Give the approximate value by rounding off.

The rounded value is 8%

The correct answer is 8%.

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