Question

A 400-Ton train runs south at the speed of 60 Km/h at a

latitude of 60◦ north.

(a) What is the horizontal force on the tracks ?

(b) What is the direction of this force.

Answer 1

Heyy!!
Here is your answer !

Final Result : 838.29N.

Let the latitude be (lambda).

For Calculation see Pics Attached to it.



Direction :

From the sketch, The Coriolis force is directed towards the west , so the force on the tracks is towards the east.
The Coriolis Force vanishes at the equator , where w× v = 0
Hope, you understand my answer and it may helps you.

Answer 2

Answer:

Here it is important to remember that the particles are called A, B, C and D and not the four corners of the sphere. Each particle changes its trajectory in accordance to its corresponding; A to B, C to D and vice versa. It is such that they spiral inwards towards the center of the square

Now as these particle would eventually meet at the center of the circle after each one has travelled undergone a displacement equal to half of the diagonal of the square (let us say it is l/2).

Now, according to Pythagoras theorem

l' = l/2 = a/√2

the velocity of each particle would be equal to v' = v.cos45 = v/√2

thus, the time taken would be

t = l' / v'

or

t = (a/v) secs.