a 40kg wagon is towed up a hill at 18.5degrees with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 140N .Assume that the wagon starts from rest. How fast is the wagon going after moving 80m up the hill
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Force parallel to the slope: Fx = mg sin @ = (40)(9.8)(sin18.5) = 124.38N since this force is down the slope it's considered negative. (You are pulling it up the slope, that force can be considered the sliding force.)
we know that Fnet = Tensional + Fx (since no fricition)
= 140N + (-124.38N) Acceleration = 15.62N / 40 A = 0.3905 m/s^2
Now you know it's starting form the rest, so it's initial velocity is zero, use this v 2 = v 2 0 + 2 a Δ x v2=v02+2aΔx
formula to find the final velocity after traveling 80m.
Hope this helps.
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we know that Fnet = Tensional + Fx (since no fricition)
= 140N + (-124.38N) Acceleration = 15.62N / 40 A = 0.3905 m/s^2
Now you know it's starting form the rest, so it's initial velocity is zero, use this v 2 = v 2 0 + 2 a Δ x v2=v02+2aΔx
formula to find the final velocity after traveling 80m.
Hope this helps.
/
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