a 40kg wagon is towed up a hill at 18.5degrees with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 140N .Assume that the wagon starts from rest. How fast is the wagon going after moving 80m up the hill
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Two forces act on wagon in the direction of the incline:
1) component of mg = mg sin 18.5° down the incline and
2) tension 140 N in the rope up the incline.
Net force up the incline
= 140 - (40) * (9.8) * (sin 18.5°)
= 140 - 124.4 = 15.6 N
Acceleration of wagon,
a = 15.6 / 40 = 0.39 m/s^2.
v^2 = u^2 + 2as = 0 + 2 * (0.39) * (80) =
=> v = √(62.4) = 7.9 m/s.
1) component of mg = mg sin 18.5° down the incline and
2) tension 140 N in the rope up the incline.
Net force up the incline
= 140 - (40) * (9.8) * (sin 18.5°)
= 140 - 124.4 = 15.6 N
Acceleration of wagon,
a = 15.6 / 40 = 0.39 m/s^2.
v^2 = u^2 + 2as = 0 + 2 * (0.39) * (80) =
=> v = √(62.4) = 7.9 m/s.
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