Question

a = 41 6 d = 7 find the t1, t2, t3 & t4​

Answer 1

Answer:

$tn = a + (n - 1)d$

$t1 = 416 + (1 - 1)7$

$t1 = 416$

$t2 = 416 + (2 - 1)7$

$t2 = 416 + 7$

$t2 = 423$

$t3 = 416 + (3 - 1)7$

$t3 = 416 + 14$

$t3 = 430$

$t4 = 416 + (4 - 1)7$

$t4 = 416 + 21$

$t4 = 437$