Question

A 45 kg boy whose leg bones are 5 cm2 in area and 50 cm long falls through a height of 2 m without breaking his leg bones. If the bones can stand a stress of 0.9 ~ 108 N m?, calculate the Young's modulus for the material of the bone. Use g = 10 m 52.​

Answer 1

Here, m = 45 kg, h = 2 m, L = 0.50 m, A = 5 * 10-m2

Loss in gravitational potential

energy = gain in elastic

potential energy in both leg bones

So, mgh = 2xstress x strain x volume

:45x10 x 2 = 2x15x0.9 x 109 x

strain x 2.5 x 10-4

Strain = 0.04

Stress_0.9x10° -2.25x109 Nm2

Y =

Strain

____

0.04

hope this will help you

answer- 2.25×10^9 Nm^-2

Answer 2

see the attachment ......

***concept :# loss in gravitational potential energy is always equal to gain in elastic potential energy in both the legs .....

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