Question

A 4500 VA load at power factor 0.75 is lagging is supplied by a 60 Hz source at effective voltage 240V. determine the parallel capacitance in microfarads necessary to improve the power factor to 0.90 leading

Answer 1

Answer:

61.8 uF

Explanation:

Capacitance needed = P [ tan∅1 - tan∅2] / w(V²)

cos ∅1 = 0.75 , ∅1 = 41.4°

cos ∅2 = 0.9 , ∅2 = 25.84°

Capacitance needed = 4500 [ tan 41.4 - tan 25.84 ] / (2 x Pi x 60 x 240²)

Solving we get, 61.8 uF