Question

A 45N object is lifted to a height of 4 metre. What is the gravitational potential energy of this object?​

Answer 1

$\boxed{\rm{\red{Question\longrightarrow }}}$

A 45N object is lifted to a height of 4 metre. What is the gravitational potential energy of this object?

$\boxed{\rm{\pink{Given\longrightarrow }}}$

• Force= 45 N
• Height = 4m

$\boxed{\rm{\green{Find \longrightarrow }}}$

• gravitational potential energy of this object?

$\boxed{\rm{\blue{Formula \ used \longrightarrow }}}$

$\sf{\red{ PE_G= mg \Delta h}}$

where,

• $\sf{PE_G}$=potential energy due to gravity
• g=acceleration due to gravity
• m=mass
• $\sf{\Delta h}$= distance above a surface

$\boxed{\rm{\orange{SoLution \longrightarrow }}}$

we know

F= m a here, {a= g}

so the value of mg= F

by Putting  value in the formula we get,

$\sf{PE_G= 45 \times 4}$

$\sf{ PE_G= 180}$

$\underline{\bf{\therefore Gravitational \ Potential \ energy \ = 180 kg m^2 /s^2}}$

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Answer 2

Answer:

hey buddy answer is

Explanation:

given force= 45 N

height = 4 m

PEg= mg∆h

= 45×4

= 180

The gravitational potential energy of the object is 180

hope it's help you mate