Question

solve this omega related sum plz​

Answer 1

Answer:

Hope this helps u...!!!

here,

w^3=1 and w^4=w...

plzz note these steps in the ANSWER.

Answer 2

hey mate here is your answer

Step-by-step explanation:

(a+b)² +(aw+bw²)² +(aw²+bw)²

=a²+b²+2ab+a²w²+b²w⁴+2abw³+ a²w⁴+b²w²+2abw³

=a²+a²w⁴+a²w²+b²+b²w⁴+b²w²+2ab2ab+2ab [where w³=1]

=a²+a²w+a²w²+b²+b²w+b²w²+6ab [where w⁴=w]

=a²(1+w+w²)+b²(1+w+w²)+6ab

=0+0+6ab [where 1+w+w²=0]

=6ab (proved)

hope that will help you

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