વીરોમા સદાવો પોષaોય કરી શાળા
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Answer:
GiventhatABCDisaparallelogram.
Weknowthatinaparallelogramoppositeanglesareequal.
Sofromthegivenfigure,
∠B=∠D⇒6x+3y−8=7y⇒6x−4y=8⇒x=
6
8+4y
−−−−(1)
Alsoweknowthatadjacentanglesinaparallelogramaresupplementary.
So∠A+∠D=180
o
⇒4x+20+6x+3y−8=180
o
⇒10x+3y=168−−−−(2)
Using1in2,
10(
6
8+4y
)+3y=168⇒80+40y+18y=168×6⇒58y=1008−80⇒58y=928⇒y=
58
928
⇒y=16
o
Usingy=
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