A-4B+2C=16
2A+7B-5C=83
a+B-C=?
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According to the question
A-4B+2C = 16 .......(i)
2A+7B-5C= 83 ..........(ii)
2× (i) shows that
2A — 4B+2C = 32
or, 2A= 32- 2C+4B....(iii)
from the equation (ii)
we can say that
2A= 83-7B +5C .....(iv)
according to the equation (iii) & (iv)
2A= 32+8B- 4C = 83- 7B + 5C
OR, 8B- 4C+ 7B- 5C = 83-32
OR, 15B - 9C = 51
OR,5B -3C = 17
OR,B = (17+3C)/5
From equation (i) , we can get
A= 16+4B -2C = 16+{4×(17+3C)}/5 -2C = (148+2C)/5
Hence
A+B-C = (148+2C)/5 +(17+3C)/5 -C = (148+2C+17+32-5C)/5 = 165/5 = 33
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