Question

5. In A XYZ, XY > XZ and P is any point on the side YZ.
Prove that XY > XP.
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Answer 1

Step-by-step explanation:

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Answer 2

In a triangle XYZ,  XY > XZ where P is any point on the side YZ.

• We can prove it by assuming a circle C1 of radius XY and centre as X

         and another circle C2 with radius XZ and centre as X.

         From the figure it is sure that C1 is bigger than C2,

        Therefore, ⇵ XY will be greater than  ⇵ XZ.

• Another way of proving is Assume 2 triangles, XYP and XPZ,

                               ∠ XPZ  ≥  ∠ XYP

        Therefore, line opposite to that will behave in the same manner,

i.e,            XY > XZ