Question

A 4cm tall object is placed 40 cm from a diverging lens of focal length 15 cm. find the position & the size of the image formed

Answer 1

Answer:

h

1

=2cm

u=−40cm

f=−15cm

v

1

−

u

1

=

f

1

v

1

−

−40

1

=

−15

1

v

1

=−

15

1

−

40

1

v

1

=

120

−11

v=−10.90cm

m=

u

v

=

h

1

h

2

−40

−10.90

=

2

h

2

h

2

=0.54cm