Question

A 4cm tall object is placed perpendicular to the principal axis
of a convex lens of focal length 24cm. The distance of the
object from the lens is 16cm. Find the position, size and nature
of the image formed, using the lens formula.

Answer 1

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Height of object ho = 4 cm

Focal length of convex lens = 24 cm

Object distance u = -16 cm

Image distance v = ?

Image height hi = ?

Lens formula: 1/v - 1/u = 1/f

1/v = 1/f + 1/u

= 1/24 + 1/(-16)

= -1/48

⇒ v = - 48 cm

The image distance is 48 cm on the same side of the lens as the object.

Magnification m = v/u = (-48)/(-16) = 3 = hi/ho = hi/3

⇒ hi = 3 x 3 = 9 cm

The image is enlarged and erect.

So a virtual, erect, enlarged image is formed at 48 cm from the optic center on

the same side of the lens as the object is positioned.

                                                                                                                                     

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Answer 2

Here's your answer in the pic