A 4kVA, 200/400V, 50 Hz, single-phase step-down transformer has equivalent resistance referred to primary as 0.15 ohm. Assuming the total iron losses equal to 60W, calculate:
(a) The total copper losses on full load
(b) The efficiency while supplying full load at 0.9 p.f. lagging
(c) The efficiency while supplying half load at 0.8 p.f. lagging
Answers
Answered by
2
Given transformer rating 4 QVA V_1 = V_primary = 200 V V_2 = V_secondary = 400 V F = 50 th R_01 = 0.15 Ohm R_01 = R_1 + R_2^'
Similar questions