Question

A=4x+1/xthen the value of A+1/A is
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Answer 1

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Answer 2

$A+\frac{1}{A}=\frac{16x^2+1+9x^2}{4x^3+x}$

Step-by-step explanation:

Given : If $A=4x+\frac{1}{x}$

To find : The value of $A+\frac{1}{A}$ ?

Solution :

$A=4x+\frac{1}{x}$

$A=\frac{4x^2+1}{x}$

Its reciprocal is,

$\frac{1}{A}=\frac{x}{4x^2+1}$

Substitute the values,

$A+\frac{1}{A}=\frac{4x^2+1}{x}+\frac{x}{4x^2+1}$

$A+\frac{1}{A}=\frac{(4x^2+1)^2+x^2}{(4x^2+1)x}$

$A+\frac{1}{A}=\frac{16x^2+1+8x^2+x^2}{4x^3+x}$

$A+\frac{1}{A}=\frac{16x^2+1+9x^2}{4x^3+x}$

#Learn more

If 4x-4x-1=24 then the value if (2x)x equals

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