Question

a) 4x2 – 4ax + (a? – 62) = 0
[CBSE​

Answer 1

Hey Mate,

Your answer is in the attachment, kindly check it from there

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Answer 2

$\large\blue{CORRECT\:QUESTION}$

$4 {x}^{2} - 4ax + ( {a}^{2} - {b}^{2} ) = 0$

$\large\red{ANSWER}$

$4 {x }^{2} - 4ax + ( {a}^{2} - {b}^{2} ) = 0 \\ 4 {x}^{2} -2( (a + b) + (a - b))x + (a + b)(a - b) = 0 \\ 4 {x}^{2} - 2(a + b)x - 2(a - b)x + (a + b)(a - b) = 0 \\ 2x(2x - (a + b)) - (a - b)(2x - (a + b)) = 0 \\ (2x - (a + b))(2x - (a - b)) = 0$

$</p><p>\large\green{EITHER}$

$x = \frac{a + b}{2}$

$\large\green{OR}$

$x = \frac{a - b}{2}$

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