Question

A(-5,1) B(1,-3) C(-2,4) are the vertices of triangle ABC. AD is median . find the point which divide AD into the ratio of 2:1


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Answer 1

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Answer 2

Answer:

ANSWER

Let AD be the median through the vertex A of△ABC. Then, D is the mid-point of BC. So, the coorinates of D are(

2

−3−1

,

2

−2+8

)i.e.,(−2,3).

∴AD=

(5+2)

2

+(−1−3)

2

=

49+16

=

65

units

Let G be the centroid of △ABC. Then, G lies on median AD and divides it in the ratio 2:1. So, coordinates of G are

(

2+1

2×−2+1×5

,

2+1

2×3+1×−1

)=(

3

−4+5

,

3

6−1

)=(

3

1

,

3

5

)

Step-by-step explanation:

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