Question

. A( 5, 1 ), B( 1, 5 ) and C( -3, -1 ) are the vertices of ∆ABC. The length of the median AD is ----------

Answer 1

Answer:

√37 units ≈ 6.083 units

Step-by-step explanation:

Coordinates of midpoint are ( $\frac{x_{1} +x_{2} }{2}$ , $\frac{y_{1} +y_{2} }{2}$ )

d = $\sqrt{(x_{2} -x_{1} )^2 +(y_{2} -y_{1} )^2}$

~~~~~~~~~

D ( $\frac{-3+1}{2}$ , $\frac{-1+5}{2}$ )

D ( - 1, 2 )

AD = $\sqrt{(-1-5)^2+(2-1)^2}$ = √37 units ≈ 6.083 units