Question

A(5,-12) b(-5,5) c(-4,-6) find the distance of each of the following point from the origin

Answer 1

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Answer 2

Given:

Three points,

A (5, -12) = (x₁, y₁)

B (-5, 5) = (x₂, y₂)

C (-4, -6) =(x₃, y₃)

To Find:

The distance of each of the following point from the origin = ?

Solution:

Let the origin be D (0,0)

Now,

Distance AD = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

On substituting the values, we get

                     = $\sqrt{(0-5)^2+(0+12)^2}$

                     = $\sqrt{(-5)^2+(12)^2}$

                     = $\sqrt{25+144}$

                     = $\sqrt{169}$

                     = 13

Distance BD = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

On substituting the values, we get

                     = $\sqrt{(0+5)^2+(0-5)^2}$

                     = $\sqrt{(5)^2+(-5)^2}$

                     = $\sqrt{25+25}$

                     = $\sqrt{50}$

                     = $5\sqrt{2}$

Distance CD = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

On substituting the values, we get

                     = $\sqrt{(0+4)^2+(0+6)^2}$

                     = $\sqrt{(4)^2+(6)^2}$

                     = $\sqrt{16+36}$

                     = $\sqrt{52}$

                     = $2\sqrt{13}$