Question

A=√5-√3/√5+√3,ab=1,find a and b

Answer 1

Answer:

a=(√5-√3)/(√5+√3)

a=(√5-√3)/(√5+√3)×(√5-√3)(√5-√3)

a={(√5-√3)^2}/5-3

a=(5+3+2√15)/2

a=(8+2√15)/2

a=4+√15

Now ab=1

4+√15×b=1

b=1/(4+√15)

b=1/(4+√15)×(4-√15)(4-√15)

b=(4-√15)/16-15

b=4-√15

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